# The BriefA Blog about the LSAT, Law School and Beyond

In our previous posts, we've talked about the basic concepts of probability and some fundamental facts about probabilities. Here, we'll show how to calculate the probability of a single event when all the outcome are equally likely. This is, in a sense, the simplest case that we will cover, and it is crucial for everything we'll do later (e.g. in finding the probability of two events occurring).

Suppose we flip a fair coin. What is the probability we get heads? Intuitively, the answer should be 1/2. And that's exactly what the following rule would say:

**Probability of Equally Likely Outcomes:
**If you have

*n*possible outcomes, all of which are equally likely, then the probability of any particular outcome occurring is 1/n.

So when we flip a fair coin, there are 2 possible outcomes (heads and tails). So n = 2 and the probability of one outcome (e.g. heads) occurring is 1/n = 1/2. And if we roll a six-sided die, there are 6 possible outcomes. So the probability of any particular outcome (e.g. rolling a 4) is 1/6. And if we held a raffle where there were 109 different entrants, the probability of any one of them winning would be 1/109.

Note that this rule only applies when all the outcomes are *equally* likely. In most GRE problems, the outcomes will be equally likely, and the question will signal that by saying that the outcome is "random" or that the outcomes are "equally likely." So, the question might say things like: "a name is chosen at random" or that "each outcome is equally likely." When the outcomes are not equally likely, all bets are off, and you will have to be more careful in how you approach the problem.

Now, we want to find the probability of some event occurring. Suppose I am going to roll a six-sided die, numbered 1 through 6. What is the probability that I get an even number? To calculate this, we use the following rule:

**Probability of Single Events (for equally likely outcomes)
**Suppose you have

*n*equally likely outcomes. Then, the probability of some event E occurring is:

where the # of total outcomes = n.

So to find the probability of rolling an even number, we need to find the number of outcomes where we roll an even number. If we roll an even number, then we must have rolled a 2, 4, or 6. Then, we divide by the number of total outcomes, in our case 6. So, P(Roll an even number) = 3/6 = 1/2.

Here’s another example in a similar spirit:

**Example 1
**Suppose you randomly choose a number from 1 to 50. What is the probability that you chose a prime number?

Now we know how to find the probability of a single event when the possible outcomes are equally likely. Our next step is to learn how to combine these probabilities in order to get the probabilities of more complex events.

**Practice Problems**

Question 1

130 people line up to buy raffle tickets. Every 10th person who buys a ticket gets a teddy bear as a promotional item. What is the probability that a randomly chosen person from the line will receive a teddy bear?

Question 2

You have 50 friends. 12 of them have blue hair. You randomly pick one of your friends to invite to dinner tomorrow. What is the probability that you invite a person with blue hair?

Question 3

You still have 50 friends. 12 of them still have blue hair. What is the probability that you do *not* invite a person with blue hair?

Next Article: Probability for Two Events to Both Occur - P(A and B)

In our previous posts, we talked about the notion of probability, some of its basic features, and how to find the probability of a single event. Here, we will find the probability of a compound event, namely an event where multiple events occur.

For example, we now know that the probability of a fair die landing on 6 is ⅙, while the probability of a fair coin landing heads is ½. But what is the probability that, if I flip a fair coin and roll a fair die, I get that the coin lands heads *and* the die lands on 6? What is probability that the coin lands heads *or* the die lands on 6?

To answer that question, we need to introduce a new idea: independence. In ordinary language, talk of “independence” suggests a rebellious child or ideas of liberty and freedom. But here, we use a different notion of independence: two events are independent if neither event affects the likelihood of the other.

An example will help to illustrate the concept. You roll a fair die and then flip a fair coin. We know that, ordinarily, a fair coin has a ½ chance of coming up heads. But now, suppose you knew that the die came up 6. Now, what is the probability that the coin came up heads? Clearly, the answer should remain: ½. The fact that the die came up 6 has nothing to do with the coin! We say that the two events are independent of one another. More precisely, we say:

**Definition:** Two events, A and B, are independent of one another if:

(i) A occurring does not affect the likelihood of B occurring, and

(ii) B occurring does not affect the likelihood of A occurring

For the purposes of the GRE, it will generally be clear when two events are independent. Here are some standard examples of independence:

- You flip a coin and roll a die. Whether you get heads on the coin ( = Event A) and whether you get 6 on the die ( = Event B) are independent.
- You draw a marble from a bag, replace that marble, and then draw a second marble. Whether the first marble is green ( = Event A) is independent of whether the second marble is purple ( = Event B). Similarly, whether the first marble is green is independent of whether the second marble is green.

Now consider the following case:

**Example 1
**A bag contains 10 purple marbles and 7 green marbles. You will randomly draw one marble from the bag and then, without returning the first marble to the bag, you draw a second marble from the bag. Is the event of getting a green marble first independent of the event of getting a purple marble second?

Here is a more intuitive way to put the same point: suppose your first marble is not green. Then it must be purple (since the bag just has purple and green marbles). That’s one fewer purple marble for you to draw next turn!

The reason why we care about independence is because independent events allow us to easily calculate the probabilities of compound events. What is a compound event?

**Definition: **Let A and B represent two events. A compound event E is the event where both A and B occur.

For example, suppose I am wondering about the weather this afternoon. Let A = “It rains.” and B = “The Broncos win their game today.” Then, the compound event A and B will be the event where “It rains and the Broncos win.” It will generally be obvious when two events are independent, and sometimes the question will explicitly state that fact. Other examples of independent events include:

- There is a bag with 10 green marbles and 14 yellow marbles. I pick a marble, look at its color, return it to the bag and pick another marble. The color of the first marble is independent of the color of the second.
- I roll a fair die, record its outcome, and then roll it again. The outcome of the first roll is independent of the outcome of the second roll.
- I randomly draw a person's name for a raffle. Then, I flip a coin. The name I draw is independent of my coin flip.

When events are independent, we can calculate the probability of both events occurring via the following rule:

**Probabilities of Compound Events
**Let A and B be independent of one another. Then, P(A and B) = P(A)P(B)

Let's see this rule in action:

**Example 2
**Suppose I roll a fair six-sided die and flip a fair coin. What is the probability that the coin lands heads and the die lands on six?

Now, this rule may seem a little odd. Why does this rule work? If you're the kind of person who needs to get a sense of why something works in order to learn it, here's an illustration that helps make the rule more intuitive.

Now, here's an application of our rule that uses larger numbers:

**Example 3
**You are wondering how poorly your day could go. You know that, at work, one employee (out of 400) will be randomly selected for additional performance reviews. And you know that there is a ⅓ chance that it rains furiously during your commute home. (Of course, whether you are selected or not for the performance review will not affect the weather.) What is the probability that you are picked for the additional performance reviews AND it rains furiously during your commute?

In our next post, instead of looking at the probability of A *and* B occurring, we will look at the probability of A *or* B occurring.

**Practice Problems**

Question 1

You roll a fair six-sided die. Is the event of you rolling a multiple of 5 independent of you rolling an even number?

Question 2

You roll a fair six-sided die. Is the event of you rolling a prime number independent of you rolling an even number?

Question 3

There are two events, A and B, which are independent of each other. P(A) = .2 and P(B) = .5. What is P(A and B)?

Question 4

You flip a fair coin 7 times in a row. What is the probability that all 7 flips come up heads?

Question 5

There are two independent events, A and B. Neither A nor B is guaranteed to happen. P(A) = .7. There are two values:

X = P(A and B)

Y = .7

Which of the following is true?

A. X is greater than Y

B. Y is greater than X

C. X and Y are equal

D. There is not enough information to tell.

Next Article: Probability for One or Another Event to Occur - P(A or B)

You're wondering whether you should go see a new action movie, *Muscle Man: How One Man's Muscles Save the World (again)*. Now, you're not the biggest fan of action movies, but you do enjoy one from time to time. So you figure it'll be worth it if you can get a good seat or if the action sequences are amazing. If neither of those things happens, then it's not worth going for you. Now, you're wondering, should I go see the movie?

Well, something that matters to you is the likelihood of: (i) I get a good seat, or (ii) the action sequences are amazing. Let A = "I get a good seat" and B = "The action sequences are amazing." You really want to know the value of P(A or B). If it's really high, then the movie is probably worth it. If it's really low, then the movie probably isn't (and buying the ticket and so on just isn't worth it).

In this section, we'll talk about calculating P(A or B), which we read as "The probability that A or B occurs." But before we do so, we need to issue an important clarification: A or B means that A occurs or that B occurs *or that both occur*. In other words, if A and B both happen, then 'A or B' happens as well. This is somewhat at odds with how we often use the word "or," as in sentences like, "You can study hard or you can fail the test," with the implication being that you cannot do both. Excise that meaning from your mind; in probability, we say that "A or B" occurs if A occurs, or if B occurs, or if A and B occur.

Now, in order to calculate P(A or B), it will help to introduce the idea of mutually exclusive events:

**Definition: Two events, A and B, are mutually exclusive if it is impossible for them to both occur.
Another way to put this (symbolically): P(A and B) = 0.**

Here are some examples of mutually exclusive events:

- When flipping a coin, getting heads and getting tails are mutually exclusive events. It is impossible to get heads and tails from the same flip of a coin.
- Suppose you and your friend have both entered into a raffle that only picks one winner. Then, the event of you winning is mutually exclusive with your friend winning.
- Suppose you are taking a class in college and you need an A or B to graduate with honors. The event where you get an A is mutually exclusive with the event where you get a B.

The point of talking about mutually exclusive events is to make it easier to calculate probabilities of one event OR another event occurring. We can do such calculations via the following rule:

**Mutually Exclusive Rule for P(A or B)
**Let A, B be mutually exclusive events. Then, P(A or B) = P(A) + P(B).

In other words, the probability that A or B occurs is equal to the probability that A occurs plus the probability that B occurs.

And if you like to get a sense for why such rules work (rather than simply memorize the formula), see here for an illustration that helps make the rule more intuitive. Now, let's see this rule in action:

**Example 1
**In rolling a fair, six-sided die, what is the probability that you will get a 1 or a 4?

Now, this rule is only a special case of a more general principle. In general, for all events, and not just mutually exclusive ones, the following is true:

**General Rule for P(A or B)
**Let A, B be two events. Then, P(A or B) = P(A) + P(B) - P(A and B).

I.e. the probability that A or B occurs is equal to the probability that A occurs plus the probability that B occurs minus the probability that A and B occur.

And again, if you like to see why such rules are true, click here. Here is an example of using this rule:

**Example 2
**You are wondering whether to go to the cafe. You would go if you knew that Bertrand or Simone was going. There is a 45% chance that Bertrand will go. There is a 20% chance Simone will go, and there is a 15% chance that both Bertrand and Simone go. What is the likelihood that Bertrand or Simone will go to the cafe?

In our next post, we will look at a strategy that can help us solve some tricky questions: instead of finding the probability of some event, try finding the probability that it does not occur.

**Practice Problems**

Question 1

In a bag, there are 5 red marbles, 2 blue marbles, and 1 pink marble. I will pick one marble from the bag, set it aside, and then pick another marble from the bag. Is the event of my drawing a blue marble on the first draw mutually exclusive with drawing a pink marble second? Is drawing a pink marble first mutually exclusive with drawing a pink marble second?

Question 2

Jane is worried that her new neighbor both (i) likes bad music, and (ii) is willing to blare his preferred kind of music at all hours. She estimates the probability that her neighbor likes bad music at .4, and the probability of his constantly blaring music at .3. And she estimates the probability that (i) or (ii) is true at .6. What probability should she assign to the worst possible outcome: her neighbor both likes bad music and is willing to blare music constantly?

Question 3

There are two events, A and B. The probability of just A occurring is r. The probability of just B occurring is s. The probability of neither A or B occurring is t. What is the probability that both A and B occur?

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On today's episode, J.Y. speaks with international student Grey Warden who scored a 170 on her LSAT.