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baileylbogle243
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Wednesday, Apr 14 2021

baileylbogle243

Allowed screen settings on Flex?

Does anyone know if it's OK to use the grayscale screen setting on your Mac during the LSAT flex? Basically, your screen is in black and white, and I'm not sure if the proctor would see that. I don't have an accommodation; it just makes my eyes feel less strained.

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baileylbogle243
Wednesday, Apr 14 2021

I'm going to be completely honest with you. I scored a 168 on my diagnostic and it still took me 3 months to get to 175+, and I'm retaking it because I wasn't able to get there consistently before my last exam. I don't think over-studying is going to fix the time issue here because of how much the LSAT can burn you out. I'd suggest splitting your studying up into two sessions a day of 1-3 hours each, with at least one full day off every week. You can probably improve to a 165+ rather rapidly but the 170+ and 175+ ranges are a bit more elusive even for the best test takers, and they require a different study strategy to reach (it's less about learning content at that point and more about drilling imo). So perhaps you should evaluate and adjust your plan as you go.

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baileylbogle243
Monday, Jun 08 2020

For 9: It's asking which one is not a COMPLETE list of researchers who could learn both S and Y in any given game solution. And, we know that S is restricted to 2 spots, and that Y is occupied by H/L/P (see below). So, let's look at the possibilities.

A) S is occupied by G and H (because G >H), and so H learns both S and Y.

B ) S is occupied by H and another researcher, like L or P. So, H/L and H/P are both possible solutions.

C) S is occupied by L and P. So, L/P is a solution.

This means are possible answers are H, H/L, H/P, and L/P. Answer choice B is not a COMPLETE list, so it's wrong.

For 11:

We know G would have to take H with it, but there's only one spot for R, so G cannot go in R.

We also know that, because there are three spots for Y, at least one of L or P will have to go there (3 spots / 4 researchers). And, since G can't learn anything L or P does, it cannot go there, so Y must be occupied by H/L/P.

So, we know that H must learn Y and that G cannot learn it. And, G must take H along with it on anything it does learn (because G>H). So H has to learn at least one more language than G, and therefore B is correct.

And, C is incorrect because you can imagine a valid solution in which G and L learn equal numbers of languages.

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