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nycabhinav722
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nycabhinav722
Sunday, Aug 25 2019

I am interested too. How do I join this group ?

Question:

How do you tell schools to not look at your file until you appear for the Jan 2020 LSAT i.e. ignore your scores so far ?

Seems like CAS will report every score after it is available but the school might not know you registered for a future LSAT and might give a decision without considering your future LSAT score.

Link:

https://www.lsac.org/applying-law-school/jd-application-process/credential-assembly-service-cas/law-school-reports

https://www.lsac.org/lsat/taking-lsat/lsat-scoring

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nycabhinav722
Sunday, Jan 12 2020

@ Wang, My bad. It is not a biconditional.

But, they cannot be in the same group right from my proof ?

Please look at the diagram here which says "Let’s start with the first constraint"

https://www.manhattanprep.com/lsat/forums/diagram-t268.html#p482

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Sunday, Jan 12 2020

nycabhinav722

PT34.S4.G4 - biconditional

Basically, my issue is with the whole explanation from JY. But for discussion sake let's focus on Q23.

If you read the question paragraph or question stem without reading Q23, you will figure out that J and K are bidirectional i.e. cannot be in the same clinic together (proof below).

So my question is why is then Q23 can have A too as the right answer choice.

Proof

s and r are locations

Js -> Kr

~Kr -> ~Js

Ks -> Jr (because only s and r are there)

Therefore, Ks (-) Jr

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Saturday, Jan 11 2020

nycabhinav722

"either or" "not both"

Stmt: Either A or B is in the forest

Question: Is "either or" and "exclusive or" here ?

My Answer:

No, because atleast 1 has to be there but not both.

A B not both

0 0 0

0 1 1

1 0 1

1 1 0

My Discussion:

"Either or" is different than "not both" because "not both" truth table is below.

A B not both

0 0 1

0 1 1

1 0 1

1 1 0

Notice the 1st line is different in both truth tables.

Question for you guys:

please see if my logic is correct

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nycabhinav722
Wednesday, Jan 09 2019

Point 1: size of M (= size of O

Point 2: all M members are also all O member but NOT vice versa(/p)

therefore, M is the NC and O is the SC, right ? (Opposite to what the answer is in the lecture).

Any thoughts ?

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Tuesday, Jan 08 2019

nycabhinav722

Sufficient condition set theory ?

I want to challenge in the following example ( https://classic.7sage.com/lesson/basic-translation-group-1-flashcards )

Each and every member of Q is omnipotent. Lecture tells us M is SC and O is NC.

However, if we use venn diagram (from set theory) and sorry for the long explanation but I cannot post pictures or draw here.

it raises questions.

Q1: Out of M or O, which "IS" the bigger set ? A1: we do not know

Q2: Out of M or O, which "cannot" be bigger than the other ? A2: M cannot be bigger than O because .... "Each and every member of Q is omnipotent" but are all omnipotent set members members of Q ? Obviously, not necessarily .

Well if Q2, A2 is right than why is O not the SC and M the NC ( not by logic but because whatever is left should fit in the remaining slot )

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Wednesday, Jan 08 2020

nycabhinav722

LSAT uber locker

Hi,

Since you probably have to uber back and forth to the test center, are cellphones allowed and can be kept outside in some locker ?

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nycabhinav722
Friday, Jan 03 2020

https://www.lsac.org/lsat/taking-lsat/about-digital-lsat

Can you go back and forth within a section and flag stuff ?

What is highlighting do ?

How big is the desk ?

Do you still get scrap paper ?

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nycabhinav722
Wednesday, Jan 02 2019

I am in but it will be remote.

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