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Embedded Conditional

Giant Panda Alum Member

February 2017 edited February 2017 in Logical Reasoning 274 karma

Hi Guys,

I was trying to prove the following statement, please help to see if it is correct:

(A-->B)-->C

not (A-->B) or C

(A some/and B) or C

C->(A some/and B)

is there more step to go below this?

So all I can get to is that, if C fails, then some A are not B.

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Comments

BryantFu Alum Member

February 2017 72 karma

The solution seems about right ...

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