PT6.S2.Q3 - Students at Pitcombe College

AspiringAttorney_

Does anyone have tips on how to tackle must be true questions when there is percentages/numbers involve because I'm having a hard time understanding why D is right

kyopoyuri

This question is just a matter of addition. So, 77% of the students endorsed a liberal position.

The students breakdown is as follows:
25% - conservative
24% - liberal
51% - middle of the road

Let's say all of the "middle of the road" students endorsed the liberal position (were part of that 77%). And then let's say all of the liberal students endorsed the liberal position too. 51% + 24% = 75%. That means at least some of the conservative students endorsed the liberal position, because that doesn't quite add up to 77% of all the students.

Alternatively, let's say all of the middle of the road students and all of the conservative students voted for the liberal position. That's a total of 51% + 25% = 76%. So at least some of the liberal students endorsed the liberal position.

And of course, if you have all the conservative and liberal students endorse the liberal position, that's only 49% of all the students, so you need some "middle of the road" students to make up the gap.

Basically, that means that within the 77% that endorsed the liberal position, all three groups are going to be represented.

So that makes D the right answer, because even if you have all of the liberal and middle of the road students endorsing the liberal position, that still leaves us with a small gap that needs to be filled, and the only other group of students are the conservatives.

AspiringAttorney_

Thanks once again! you're the best