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This is the question I found in PT 19 section 1, third game.
If F is assigned to b2, G is assigned to b2.
If V is assigned to b1, W is assigned to b2.
Does it mean that if F is in b1, G can be b2 or b1?
Does it mean that V is in b2, W can be in b1 or b2?
I follow the logic F b2 -> G b2, but not the opposite direction, so G can be in any position when F is in b1.
I hope it is correct.
Comments
You got it! Good job.
Also note that if G is not assigned to b2, F is not assigned to b2. The same goes for W and V.
Yes!! Thank you so much for answering my question!
Thanks for the the principle you pointed out as well! I understand it but somehow I just don’t list it in my mind when I first read the conditions.
I guess practicing with more questions could improve this problem~
Yes you are correct, also, F and V might not be "in" at all, which also means that G and W can be anywhere.
If you fail the sufficient, the rules falls away.