Conditional linkage

Comments

• 1 Like

  Logician Alum Member Sage ⭐

  October 2020 2464 karma

  No- here’s why. While it would be true in that if you have A and B then you must have C, that logical representation would be excluding two other valid possibilities:
  1) just A
  2) just B

  Both of these possibilities are sufficient for concluding C. So while it would not be inaccurate per say to represent it as A + B —> C, it would be an incomplete representation of the logical relationship, seeing as it’s excluding two other possible worlds (only represents 1/3 of the worlds).

  the correct representation would be:
  A or B —> C

  In this representation, 3 possibilities exist that are each sufficient to trigger the necessary.
  1) just A
  2) just B
  3) A and B
• 2 Likes

  LOWERCASE EVERYTHING Member ⭐

  October 2020 1952 karma

  it might be helpful if you look at the contrapositives. the correct inference is /c --> /a and /b which is totally different from the incorrect inference: /c --> /a or /b.

  by the way, you can also conclude: /a some /b