PT92.S2.Q10: If Felicity lives alone in #2

Comments

• Jackelopes Member

  January 2022 4 karma

  3 Columns: 1,2,3. J is in 3. H is with only one other in 1 or it is in 2 with potentially up to 2. If its in 1, then 2 is a P, J is partnered with a NP. If H is in 2, then it can either can 1 or 2 with it.
• 1 Like

  5Fennel LSAT Member

  January 2022 192 karma

  FGHJK ppp, infer nn
  1: _ _
  2:
  3: Jn

  1. 1 empty max
  2. n -> /p
  3. F -> /G
  4. apt1: _ _ max
  5. Hp+_p
  6. apt3: Jn
  

  Key Inference:
  n-> /p and apt3:Jn and Hp+_p restricts to 4 possible distributions of ppp nn,
  FGK remain.
  If 2 open spots in same apartment, F/G cannot both be in, forces K into one of the empty spots.

  1: Hp _p
  2: _p
  3: Jn _n
  FGK any remaining spot

  1: _p
  2: Hp _p
  3: Jn _n
  FGK any remaining spot

  1: empty
  2: Hp Kp _p
  3: Jn _n
  FG any remaining spot

  1: _n
  2: Hp Kp _p
  3: Jn
  FG any remaining spot
• lsatqueen-1 Member

  January 2022 12 karma

  THANK YOU GUYS