diagramming conditional within conditional

Comments

• LSATisland Free Trial Inactive Sage

  December 2013 1878 karma

  You got it. The first condition is triggering a second condition. It's good that you placed the second condition in parenthesis as a reminder that the second condition is an independent equation.
  
  The contrapositive would be if you negate the second condition, contradicting the truth of the condition. According to the second condition, if you must apologize to someone, you must apologize to both. If you can prove a situation where you must apologize to someone, but not necessarily both, then it cannot have been an apology for an identical lie told to two people.
  
  If you can contradict the truth of the second condition, then the first condition could not have existed.
  
  I hope I wasn't confusing.
• jane1010 Free Trial Member

  February 2014 14 karma

  thanks so much for the quick reply. let me know if i understood you correctly:
  
  given: "someone tells the same lie to two different people --> (at least one owed apology --> both owed apology)"
  contrapositive: someone tells the same lie to two different people --> (both not owed apology --> neither owed apology)
  
  and this is because the negation of a conditional, A --> B is A -->~B, correct?
• 1 Like

  LSATisland Free Trial Inactive Sage

  February 2014 1878 karma

  I would phrase the contrapositive by beginning at the opposite end, by negating the second conditional. It would be a bit abstract in this case: If we are discussing a case where you can owe one person, but not both, and apology --> then we cannot be discussing a case where a person said same lie to two people.
  
  It follows the same method as a normal condition:
  
  Normal condition: A --> B
  Negation: ~B --> ~A
  
  Double conditional: A --> (C --> D)
  Negation: First show we are discussing case where C-->D doesn't apply (i.e. C-->~D or ~D-->C). Once the (C-->D) rule is inapplicable, A must be as well.
  
• 1 Like

  J.Y. Ping Administrator Instructor

  February 2014 14205 karma

  Hey guys, sorry to butt in.
  
  There's a lesson on embedded conditionals:
  http://7sage.com/lesson/mastery-embedded-conditional
  
  Also a lesson on negating conditionals:
  http://7sage.com/lesson/advanced-negate-all-statements/
  
  Okay, that's all. Please carry on!
• Lime Green Dot Member ⭐

  May 2021 edited May 2021 1384 karma

  So... just to clarify:

  If we're starting out with "if someone tells the same lie to two different people, then neither of those lied to is owed an apology unless both are,"

  I'd have diagrammed it like this:

  Tells same lie to both → (~Both owed apol → ~1 owed apol and ~2 owed apol)

  Getting rid of the embedded conditional (i.e., taking out the parentheses) yields:

  Tells same lie to both and ~Both owed apol → ~1 owed apol and ~2 owed apol

  So I get the contrapositive as being:

  1 owed apol. or 2 owed apol → ~Tells same lie to both or Both owed apol

  If this looks okay, I guess I'm not sure where negating an 'all statement' (the 2nd referenced video lesson) would come into play?

  Could someone help me understand this?