... to have both P and L in. How JY diagramed it ... P then we must see L. What if we see P ... rule goes away and L becomes a floater. L can be in ...
... , the necessary must follow, forcing L to be in. That's ... can do whatever. So now L has two options: in or ... out.
a. When L is out, that's fine ... rule covered.
b. When L is in, now they're ...
... />
**Rule 2:** Z1 -> L - O (-> L/6 -> M/3 ... )
If L - O then L cannot be 6, so ... two rules both talk about L, specifically, L in 6.
< ... certain sufficient condition leads to L being locked out of ... 2 (Z1 -> L - O (-> L/6 -> M/3 ...
... in, or O and L are both out. Formally:< ... br />
(O & L) -> Y
(/O and ...
On '/Y → (L↔/O) = /Y and L ↔/O.' This seems false ... to me. (/Y and L) does necessitate /O, but ... should also necessitate (/Y and L). /O could also work ...
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