PT7.S4.Q19

PrepTest 7 - Section 4 - Question 19

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Support It takes 365.25 days for the Earth to make one complete revolution around the Sun. █████████████ ██████████ █████ █ ████ ███ ████ █████ ████ ██ █████ ███ █████ █████ ██████ █████ ███ ███ ████ ██ ███████ ████ ██ █████████ ██████ ███ █████ ██ █████ █ ██ ████ ████ █████████████ ██ ███ ████ ██ ███ ████ ███ ██ ███ ████ ████ █████ ████ ██████████ ████████ █████ ██ ███████ ██ ███ ████ ███ ██ ████ ████ ███ ██ ██████████ ███ █████ ██████ ████ ████████ ██ ██ █████ ██ ████ ███████ █ █████ ██ █ ██████ █████ █████

Argument Structure

This stimulus points out that the time it takes for the Earth to revolve around the sun — i.e., the actual duration of a year — is 365.25 days. The stimulus then describes the convention followed by the current calendar to accommodate this fact: treating a year as 365 days, with an extra day every four years, and dividing the year into 52 weeks.

The stimulus then notes that 52 7-day weeks actually make up only 364 days: i.e., the 365-day year does not divide fully into seven-day weeks. The result of this is that anniversaries — i.e., days that have the same calendar date every year — don't fall on the same day of the week each year.

The stimulus concludes with a proposal meant to resolve "many scheduling problems": treating the last day of the year, and an additional "leap day" every fourth year, as "belonging to no week." This way, the week would "restart" with the year, with January 1st being a Sunday each year.

Notable Assumptions

It's important to understand exactly what the problem is that the stimulus is highlighting. The stimulus points out that because the year has 365 days, but is divided into 52 7-day weeks (i.e., 364 days), anniversaries don't fall on the same day of the week each year, because there is one extra weekday each year that "sets back" the next year by one weekday. In other words, if your birthday is on August 14th, it might be on Wednesday one year and Thursday the next.

To solve this issue, the author suggests treating the last day of the year — and an extra day every fourth year — as "belonging to no week." In other words, December 31st (and probably February 29th in leap years) would be considered "non-weekdays." This would allow 52 whole weeks to fit into the year, and then the count would start again on January 1st, which would be a Sunday every year.

This strategy would allow the calendar date of an anniversary to correspond predictably with a specific day of the week. With this system, if August 14th was a Wednesday one year, it would also be a Wednesday the next year. If something were scheduled for December 31st, you would know it was scheduled for the "non-weekday."

So this proposal does solve the issue of anniversaries falling on different weekdays each year. The stimulus, however, assumes that this issue causes "many" scheduling problems, which isn't clear. Also, while this proposal might make scheduling yearly events easier, the stimulus doesn't consider the effect this proposal would have on scheduling weekly events. For instance, if you had to take a certain medication three times a week, meaning you currently took it on Monday, Wednesday and Friday, you would have to figure out how to factor in the "non-weekday" into the count every December 31st, which might make scheduling more complicated.

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19.

The proposal above, once put ████ ███████ █████ ██ ████ ██████ ██ ██████ ██ █████████ ██████████ █████████ ███ █████ ███ ██ ███ █████████ ███████

a

people who have █████████ ██ █████ █████████████ ██ ████████ ██ ██ ██

b

employed people whose ██████ █████████ ███████████ ███████ ████ ████ ███████ ████ ███████ █████ ███████ ███

c

school systems that ███████ ████████ ██ ██████ ███████ █ ████████ ██████ ██ ████ ████ ████

d

employed people who ████ █████████ ██████ ████ ████ ████ ████████ ███ ██████████ ██ ███████ ██ ███████

e

people who have ██ ████ ██████ ███████ █████ ██████ █████ ██████ █████

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