The last problem also fits the X, Y, Z structure. Just in a different order. So instead of "Most X are Y. All Y are Z. Thus, most X are Z.", the problem is structured backwards "Thus, most X are Z. All Y are Z. Most X are Y."

• Most (X) are (Y): "Most chefs ((X) have extensive culinary knowledge (Y)."

• All (Y) are (Z): "All chefs with extensive culinary knowledge (Y) can make a delicious omelet (Z)."

• Conclusion (Most (X) are (Z): "Most chefs (X) can make a delicious omelet (Z)."