LSAT 11 – Section 2 – Question 07
LSAT 11 - Section 2 - Question 07
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| Question QuickView |
Type | Tags | Answer Choices |
Curve | Question Difficulty |
Psg/Game/S Difficulty |
Explanation |
|---|---|---|---|---|---|---|---|
| PT11 S2 Q07 |
+LR
| Must be true +MBT | A
11%
157
B
5%
160
C
13%
161
D
70%
166
E
0%
158
|
143 154 165 |
+Harder | 148.469 +SubsectionMedium |
We have a must be true question here, as the stem demands: If the statements above are true, which one of the following must on the basis of them be true of woolly monkeys in colonies?
This is a very short, straightforward stimulus. Our first sentence begins with the conditional indicator every. If we translate this first conditional, we should see that just being an adult male woolly monkey is enough to be larger than all female woolly monkeys. Our second sentence adds on to this information with another conditional, indicated by the sufficiency indicator any. From this we learn that an adult male woolly monkey is capable of dominating all females. Ok, so the adult males are always larger than and capable of dominating the females, got it. Since this is a must be true question and all our stimulus gives us is two conditionals which cannot be chained, we should expect the inference will either involve a contrapositive or a simple triggering of one of the conditionals leading to its necessary condition. Let’s see what we get.
Answer Choice (A) This answer might be appealing because there seems to be a strong correlation between the men being all larger than the females and all capable of dominating them, but this inference requires that we assume this correlation entails that size is the primary determinant, and there aren’t any other possible determinants which we just haven’t heard about. A must be true inference will never require an assumption.
Answer Choice (B) Our rules have only been about adult males, we can’t infer anything about the adolescents with certainty.
Answer Choice (C) Again we have to read carefully here; we only know about specifically adult males, so we can’t infer this general rule about all males. What if some adolescent males are larger than females but won’t dominate them yet.
Correct Answer Choice (D) This is just the contrapositive of our second rule. If a male doesn’t dominate a female, then the male must not be an adult male.
Answer Choice (E) This must be false, as we’ve been told any adult male will dominate any female; this answer choice would entail that adult males won’t dominate some females.
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LSAT PrepTest 11 Explanations
Section 1 - Logic Games
Section 2 - Logical Reasoning
- Question 01
- Question 02
- Question 03
- Question 04
- Question 05
- Question 06
- Question 07
- Question 08
- Question 09
- Question 10
- Question 11
- Question 12
- Question 13
- Question 14
- Question 15
- Question 16
- Question 17
- Question 18
- Question 19
- Question 20
- Question 21
- Question 22
- Question 23
- Question 24
- Question 26
Section 3 - Reading Comprehension
- Passage 1 – Passage
- Passage 1 – Questions
- Passage 2 – Passage
- Passage 2 – Questions
- Passage 3 – Passage
- Passage 3 – Questions
- Passage 4 – Passage
- Passage 4 – Questions
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