With the approach of the twentieth century, the classical wave theory of radiation—a widely accepted theory in physics—began to encounter obstacles. ████ ██████ ████ ████ ███ ███████████████ ███████████████ ██████ ████████ ████ █████ ███ █ ████ ██ █████ ████████████ █████████ ████ ███ ██████████████ ██ ███ ████ ██ ██████ ███
Challenge to Existing Theory ·Classical wave theory claims that all radiation exists as waves
If this theory is being challenged, that must mean that some (or all?) radiation doesn't take the form of waves?
Theory's Assumption ·Wavelength and energy are continuous
Continuous means that any conceivable energy value could occur in nature. But if that's the assumption, then it probably will turn out to be false. So... what's the opposing concept to "continuous?"
Phenomenon (Unexplained by Wave Theory) ·"Blackbody" radiation
"Blackbody" radiation is the heat(?) emitted by an object. The object is black so that it doesn't reflect other forms of radiation (e.g., light in the visible wavelengths). That way, physicists can be sure that they're measuring radiation emitted by the object, as opposed to radiation that merely bounced off that object.
Prediction False ·Physicists found almost no short wavelength radiation
The theory predicted that they would find a lot of short wavelength radiation, e.g., ultraviolet radiation. But experimental results contradicted that prediction.
New Hypothesis ·Planck theorized that energy was discrete
Planck discarded wave theory's energy continuum (like a smooth turning dial). He didn't think that energy could take on any value. He hypothesized that energy could only take on discrete values. So to move from one energy level to the next involves a jump (like a dial that clicked into place).
New Theory ·Einstein theorized that radiation is composed of particles called photons
Photons can be emitted only in discrete units and at certain wavelengths, corroborating Planck's hypothesis.
Passage Style
Phenomenon-hypothesis
Single position
19.
Which one of the following ███ ████ ███████ ██ ████████ ████ ███ ███████████ ██ █████████ ███████ ██ ███ ██████ ██████████
Question Type
Implied
At the beginning of P2, the author tells us that blackbody objects are required to measure thermal radiation, because we need objects with little or no reflective capability in order to be sure that we’re measuring thermal radiation instead of reflected radiation.
Let’s keep that in mind when we go to the answers.
Supported. If (A) were not true, then it wouldn’t make sense for measurements of thermal (emitted) radiation to “require” non-reflective objects. We’d simply be able to distinguish the radiation emitted by an object and that which comes from reflection and pay attention to only the emitted radiation.
b
Any object in █ ████ ████ ██ █ ██████ █████ █████████ ███████
Not supported, because we don’t know that “any” object has little or no reflective capability.
This is a difficult question.
It is similar in difficulty to other questions in this passage.
CURVE
Score of students with a 50% chance of getting this right
25%142
156
75%169
Analysis
Implied
Phenomenon-hypothesis
Science
Single position
Answer Popularity
PopularityAvg. score
a
62%
164
b
3%
158
c
12%
157
d
14%
161
e
9%
157
Question history
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