Practice LSAT Prep Test 63 (June 2011) - Section 2 (Logic Games) - Game 4

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JY's explanation:

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Prep Test Question Keywords: street, entertainer, six, boxes, top, numbered, consecutively, 1, 6, lowest, highest, green, red, white, onlookers, guess, ball, box


PrepTest 63 - Question explanations

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  • LSATGamesTutor.com

    It didn’t prevent the correct answer from being chosen, but the solution to question #19 incorrectly deduces that WG must go in spots 1 and 2, making the only possible order WGRRGG. WG could also have gone in spots 4 and 5, making an alternative order GRRWGG.

    • http://7sage.com/ J.Y. Ping

      You are correct. Thanks for pointing that out!

  • Patrick Taqui

    I found it useful to plot the total number of balls possible given the restriction regarding rule #1 combined with the other 2 rules.
    If there’s 1 white ball, there are at minimum 2 and up to 4 red balls, with a corresponding number of green balls. That’s 3 numerical distributions.

    If there are 2 white balls there can only be 3 red balls because there must be 1 green ball leftover. Thus there are 4 possible distributions. This helped me recognize which possible distribution could be used for each local question.

    Hope that helps.

  • tashi topgyal

    What is the reason for trying “W?”

    • J.Y. Ping

      The question is asking which slot must have an item in it which also appears in another slot. In other words, it’s asking which slot cannot be solitary/unique. We’re eliminating the answer choices by proving that 4 of them can be solitary/unique. We know that there must be multiple R’s, so we wouldn’t try R (premise 1). Between G and W, I picked W because W is freer than G to appear only once. G has premise 2 ruling it which puts pressure on it to appear more than once. W on the other hand, has no pressure at all to appear more than once. Think about it. Let me know if you want further clarification.

      • Nick Saucedo

        Basically, for “must be true” questions we are trying to prove and eliminate the answer choices that “could be false?”

        • J.Y. Ping

          Yup! That’s one way to do it. The other way is to prove that the answer choice “must be true.” Which method you use depends on what inferences you can draw ahead of time.