So on question 12 JY mentioned a bi conditional because there was a /S-->H, /H-->S, and also a S-->/H, and a H-->/S. However, to get the first set of conditionals, the original chain was /S-->J-->H. Can you simply say that this= /S-->H? I wasn't aware that you could do this. In a conditional chain don't you need all the elements? Or can you just remove the J and write this as another separate statement? This doesn't make sense to me

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https://classic.7sage.com/lsat_explanations/lsat-33-section-4-game-2/