Can someone please help me diagram and understand the inferences made from these statements?
Some As are Bs.
All Cs are Ds
No Bs are Cs.
Here is what I have so far.
AsomeB—-> ~C
~D—->~C
Inference: Asome~C
0
Can someone please help me diagram and understand the inferences made from these statements?
Some As are Bs.
All Cs are Ds
No Bs are Cs.
Here is what I have so far.
AsomeB—-> ~C
~D—->~C
Inference: Asome~C
5 comments
Here is how you do it:
If we have these two conditional statements:
X —> Y
Z —> Y
We can’t infer anything...
However, if we take the contra-positive of those two conditional statements, we get the following:
~Y —> ~X
~Y —> ~Z
From there we can infer that ~X (—S—) ~Z
The reason behind that is the following: ~X and ~Z must share some common-ground or, as JY says, some interception because ~Y is brought into ~X and ~Z...
I hope this helps - good luck studying!
Some As are Bs: As (---S---) Bs
All Cs are Ds: Cs ---> Ds
No Bs are Cs: Bs ---> ~Cs
Linking them will look something like this:
As (---S---) Bs ---> ~Cs
~Ds ---> ~Cs
(I can't find a way to connect Bs and ~Ds to ~Cs, but if you are writing this down, you should connect them...)
Anyway, the inferences are:
As (---S---) ~Cs
~Bs (---S---) Ds
I hope this helps!
Of course, let me know if you have any other questions.
@fyepes582 Thank you so much!!
@fyepes582 Thank you for the reply. How did you make the inference ~B (--s--) D? I am having trouble making that inference.