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seroujsg241
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seroujsg241
Friday, Jul 26 2024

I am interested

I have a question regarding Conjunction and Disjunction when they’re present in the sufficient and/or necessary condition.

I know “and” does not split in the sufficient condition and does split in the necessary condition and vice versa for "or" statements.

Does that mean if a statement says “A and B -> C” that we need both A and B to be present to trigger the necessary condition? Or 1 of them alone would be enough to trigger.

Conversely, if it said “A -> B and C”, does A being present mean both B and C must be present together as a consequence? Or one can be present without the other?

Thank you for taking the time to respond.

PrepTests ·
PT151.S3.Q4
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seroujsg241
Monday, Jul 22 2024

I have a question regarding Conjunction and Dis-junction when they're present in the sufficient and/or necessary condition.

I know "and" does not split in the sufficient condition and does split in the necessary condition.

Does that mean if a statement says "A and B -> C" that we need both A and B to be present to trigger the necessary condition? Or only 1 of them would be enough to trigger.

Conversely, if it said "A -> B and C", does A being present mean both B and C must be present together as a consequence? Or one can be present without the other?

#feedback

#Help

PrepTests ·
PT151.S2.Q15
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seroujsg241
Sunday, Jul 21 2024

I think knowing how much is a "significant amount" was important on this question. I created a scenario in my head where a street has:

10 old house. And we know there are 2x as many apartments as old houses, so based on this scenario, the apartments cannot exceed 20.

So we have 10 old houses and 20 apartments. And the conclusion is that most of the old houses have more than 1 apartment. The flawed assumption is that EVERY old house has an apartment AND that the distribution of apartments is equal, but we have no reason to believe that. What if one house has all 20 apartments and the others have none? that is extreme, but could be a possibility.

What answer E does is it tells us a significant number of house have more than 3 apartments, which exposes a vulnerability in the author's argument. If we assume 4 old houses is a significant amount, and we assign 5 apartments to each of those 4 houses, we get 20 apartments. We can then have the other remaining 6 houses have 0 apartments. Because the author did not account for this possibility, his argument that "most houses have more than 1 apartment" is under threat. Anyone can look at his conclusion and make a counter argument like the one above.

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seroujsg241
Sunday, Aug 04 2024

Low Res

Hypo 1 - Cataclysm and Solar system

Hypo 2 - /Cataclysm and Solar system

Hypo 3 - Cataclysm and /Solar system

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