I'd like to share my method I used for this game. I thought this game fell into the category of "sounds weird and looks weird, but is actually simple". This seems to be a pattern seen in the 4th game of many 70s.

A very simple way to look at this game would be to think of it as a sequencing game.

Ex. If it says A transferred to B, I would diagram it as A-B

If says A transferred it to 2 other computers, then I would think of the diagram as A connected to exactly 2 lines on the right.

For the rule "S transmitted...", I would have S with exactly ONE letter connected to the right (ie S-__). Also note, I could have something connected to the __ because that wouldn't be connected to S.

For the rule "..to R also .. S", this would be diagrammed as __-R with that same "__" connected as __-S. That should look like __ with 2 things to the right of it (those 2 things being R and S). Now combine this rule with the previous rule about S and your result should look like __ connected to R and connected to S. And S connected to exactly one other thing (don't know what yet).

At this point you might want to think about what could be the first __ that transfers a virus to R and S. Our remaining letters are P,Q,T,U. As for what S will transfer to will also be one of those 4 letters (at this point). Please also remember that each letter can only receive the virus once, meaning there is at most only one letter directly connected to left of a given letter.

Finally, we find out either R or T transmits to Q and either T or U transmits to P. This gives us a lot of information because now we can start to figure out what goes in each blank. By simply placing 1 letter that transfers to both R and S, almost everything else will trigger and fall into place.

I hope this helps simplify the virus game. If you're still a little confused, I can go into more details and break everything down.

https://classic.7sage.com/lsat_explanations/lsat-68-section-4-game-4/

Hi, I'd like to share a method I used for pt68 game 4. At first glance, it seems like you have to brute force this game; however, you can solve it in a more efficient manner. With this method, this game took me a little under 9 min. Before starting this explanation, I will assume you understand the rules but let me know if you would like that explained as well.

The first step is to understand what the possibilities are in this game. It seems like anything could happen, but we are actually quite limited once we apply a few rules. One technique I found helpful in this game (and other similar ones) was to split via the Q3 rule. One with Q3 (therefore making the rule irrelevant) and one with Qnot3 (therefore triggering Q-S). By doing this, we no longer have to worry about whether or not to apply the conditional rule. Another thing I added towards my rules was that there must be something in between J and G (since they are both finance); the rule ended up looking like this J-X-G-R (just remember the X means "something"). This same concept can be applied to the Qnot3 rule; the result is Q-X-S-Y (the X here and the other X does not necessarily have to be the same thing, it's just there to represent the "something" that has to be there).

So let's start with the Q3 game board. With Q3, next we want to look at J; J has a minimum of 3 things after it so it would seem the only possible spots for J would be 1,2,4. It turns out 1 is not possible because there's nothing that can go in between J (1) and Q (3) other than Y, but Y has S before it. Therefore, we only have to look at J in 2 and 4. Whether J goes in 2 or 4, G and R must go after Q, otherwise we would violate the consecutive rule. If J is 2, we need something in 1 that is NOT finance. This means either S or Y, but not Y because of the S-Y rule. If J is in 4, G must be in 6 (can't put G next to J) and R must be in 7. To go in between J and G, we need something thats NOT finance. Again, this means S or y, but not S because of the S-Y rule again. This leaves us with S and H for 1/2 but since Q and S are of the same group, they must be separated by the H.

Gameboard 1.1 S J Q _ _ _ _ G-R, Y, H These 4 letters can go anywhere as long as they maintain the sequence required and the no consecutive rule. There's a few possibilities here, but it's really not that many nor is it complicated to see.

Gameboard 1.2 S H Q J Y G R (it's completely filled!!)

Next up is the seemingly complicated Qnot3 split. It ends up not being filled in at all, but we only have to remember 2 sequencing chains. As mentioned earlier, Qnot3 triggers our conditional rule leaving us with Q-X-S-Y. This sequence along with the previous J-X-G-R sequence is all we have to keep track of, and H. Once we place one letter, things will start to fall into place.

Gamebaord 2 _ _ _ _ _ _ _ [Qnot3] Q-X-S-Y J-X-G-R H(just dont put this next to G or J)

The questions go by pretty quickly.

I'll skip question 17.

Question 18. If Y is 4th... it is best to just look at one gameboard first to see what we can eliminate quickly. Let's put Y4 into 1.2. The result is S J Q Y G R H. B, C, E get eliminated. So we are left with A (J2) and D (Q3). The next board to look at is our only other possibility, which is 2. If Y is 4, then according to our sequence, we must have Q-X-S in 1,2,3 respectively. J can't 5,6,7 since there's 3 things after it so the only spot left for J is 2. The result is Q J S Y G R H. A (J2)

Question 19. If G is 4th, could be true, let's look at a board that has a lot filled in (ie 1.1) So S J Q G _ _ _ with R Y H to place. Scanning the answer choices quickly, you should see E (Y6). We can simply have S J Q G R Y H. E (Y6)

Question 20. Quick and easy, scan through the choices to see if we have anything filled in from our boards. B (H2)

Question 21. For this question we will have to do a bit of work, but nothing too hard since we only have simple rules to follow. If J is 3, we can only be looking at gameboard 2. _ _ J _ _ _ _ ... X-G-R will go to the right of J. What can go to the left of J? We can't put S on 2 because there's 2 things before it and we can't put Y on 2 because there's 3 things before it, so we're left with Q and H; H and J also can't go next to each other so we must have H Q J _ _ _ _ S-Y G-R . Since this is a could be true, the answer choice will most likely be one with S, Y, G, or R. That leaves us with A, D, E. G can't be 4th since J is 3rd [BYE A]. S can't be 2nd since Q is 2nd [BYE D]. Y 5th is ok ... H Q J S Y G R E (Y5)

Question 22. S could be what except...check your previous work!! S1 is in 18. S3 is in 18. S4 is in 21. We don't have anything for S5 or 6, but that's ok because now we only have to test 1. I would choose S6 because that will force Y7. _ _ _ _ _ S Y (this will be gameboard 2 so just fill it in using our remaining sequence chains) We can have J Q G R H S Y. S6 works so our answer will be D (5)

Question 23. To do this question most efficiently, you'll have remember our earlier rules about sequences. If we put R4, that forces J-X-G into 1,2,3 respectively thus placing us in gameboard 2. J _ G R _ _ _ Q-X-S-Y H The only thing that can go in between J and G is Q and H, but not H since it's finance (along with J and G) therefore.. J Q G R _ _ _ S-Y H R and S are both nutrition therefore we are forced into this result J Q G R H S Y C(R4)