LSAT 124 – Section 3 – Question 19

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Question
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Type Tags Answer
Choices
Curve Question
Difficulty
Psg/Game/S
Difficulty
Explanation
PT124 S3 Q19
+LR
Must be true +MBT
Conditional Reasoning +CondR
A
93%
164
B
1%
153
C
1%
150
D
5%
157
E
1%
155
129
138
148
+Easier 145.896 +SubsectionMedium

Please note that the question stem does not stipulate that the three authors are the only authors who could be included. Therefore, we must not presume that there are no other authors.

We’ve got an MBT question here, which we can tell based on the question stem: If the statements above are true, which one of the following must be true?

We’ve got a stimulus here that almost reads like a set of logic games rules. We know that we’ve got a textbook that will have essays written by some combination of Lind, Knight, and Jones, but not all three. We also know that if the book has an essay by Knight, it will also contain an essay by Jones (so K→J).

So what are our possible sets of authors: Well what do we know? KJ is definitely a possibility. We could also always have a book that only features one author ( assuming that author isn’t K because of the aforementioned rule), so we can add “J” and “L” to our list. And then of course we could have a combination of J and L. So all the possible options of authors should look like this:
J
L
KJ
JL

This synthesizes all the rules we’ve been given, so let’s move on to the answer choices:

Correct Answer Choice (A) This fits with what we’ve determined. There is only one possible set that contains Knight: KJ. Therefore, this is correct.

Answer Choice (B) This is incorrect. We have two possible sets that contain two authors.

Answer Choice (C) This is incorrect. We have one possible combination in our list that includes Knight.

Answer Choice (D) This is incorrect. It is possible for Lind to appear on their own (i.e. without Jones).

Answer Choice (E) This is incorrect. We have two possible sets that do not include Lind.

 

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