I have:

G most F

------------------

C some G

I am trying to conclude C some G, but I am a bit confused.

To me this: G most F ---> C concludes G most C, and not G some C.

Can G most C and G some C be used interchangeably in this instance?

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6 comments

  • Thursday, Oct 20 2016

    Yeah you are correct--you can conclude that. It really helped me to hone in and memorize the combinations of some and most intersections so that when I went to a stimulus, I was able to immediately see what forms were valid and which ones were not.

    1
  • Thursday, Oct 20 2016

    Yup :)

    1
  • Thursday, Oct 20 2016

    @nessak130467.k13.0 No they can't be used interchangeably. Most and most can = some but most and some cannot equal some just as some and some cannot yield some.

    If I have:

    G most F ----> C

    In this instance, Can't I conclude both?:

    G most C

    and/or

    G some C

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  • Thursday, Oct 20 2016

    @rahelaalam514 inherent inferences

    I understand what you're saying.

    If I have:

    G most F ----> C

    In this instance, I can conclude:

    G most C

    and/or

    G some C

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  • Monday, Oct 17 2016

    Well if you get to a conclusion thats G most C, you can draw out the inference that there is also G some C. I believe powerscore calls them "inherent inferences".

    For example "if most chocolates are brown" then we can also infer from that "some chocolates are brown" or "some brown things are chocolates". But just be careful because some can never become most because this is only a one way relationship. All implies most, most implies some.

    https://classic.7sage.com/lesson/advanced-all-implies-most-implies-some/

    I think in the case above if from G most F-->C you conclude G most C, you can conclude G some C; since some relationship is reversible you can say C some G.

    *btw I could have totally missed what you were actually asking.

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  • Monday, Oct 17 2016

    No they can't be used interchangeably. Most and most can = some but most and some cannot equal some just as some and some cannot yield some.

    1

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