Subscription pricing
In his video on EC, JY discusses the example A ----> (B---> C), where the embedded part is second, and it becomes A + B ----> C. But what if the embedded conditional is first [(A--->B) ----> C], what would the mechanical rule be then? Do we say that A----> B + C?
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Also interested in this. Frequently I'd come upon the latter embedded and realize it's not the same structure and can't make the translation.