Can anyone point me to the lesson on diagramming for 'some' ?
For example: Under the Sufficient Assumption & Psuedo-Sufficient Assumption Section, Lesson 6, I need help remembering how to navigate the diagrams that involve "some."
https://7sage.com/lesson/quiz-on-finding-sufficient-assumptions-with-intersection-statements-1-answers/?ss_completed_lesson=11893We're given premises with one premise missing that helps us arrive at the conclusion. In this case:
F <--some--> U
[find missing premise]
-----------------------------------
U <--some--> /I
For the life of me I'm having a hard time navigating "some" when diagramming. Any help or letting me know which lessons to review would be greatly appreciated!
Comments
I think 'Some(P & Q)' has a ton of benefits over your biconditional-like diagram. First, it makes it obvious that "some" takes the widest scope in the sentence, so that the negation is a "not some" sentence, which is equivalent to an "all not" sentence. Second, it uses the conjunction ("and") symbol, so that you get all the properties of "and", such as commutativity (i.e. some P's are Q's implies some Q's are P's). I think the most important property with the "and" is that you can see how existential sentences are nicely equivalent to negated universal sentences, in virtue of De Morgan's laws.
This is what I'd personally recommend, but I imagine others here who subscribe to the "LSAT" method might disagree.
Here's a short breakdown of "some" diagrams.
"Some fish are orange" = "Fish, some orange" = F <-Some-> O (or the other way around, it doesn't matter).
If you're trying to draw an inference with a "Some" statement, the "Some" must be on the sufficient side.
"Some fish are orange. All things that are orange are colored" = F <-Some-> O ----> C =
F <-Some-> C (Some fish are colored)
If it were reversed (O ----> C <-Some-> F) no transitive conclusion could be properly drawn.
This is one way to draw an inference with a "some" statement.
-2 Some statements alone = No valid conclusion
-1 All statement and 1 Some statement, where the "Some" is in the necessary condition = No valid conclusion
-1 Most and 1 Some statement = No valid conclusion
You can also draw a valid conclusion with a "some" and "All" statements, if they share the same sufficient condition.
Completed chain: U <-some-> F --> /I
Mechanical rule: Follow the arrows. The Some relationship transfers only if the arrow is moving AWAY from the Some relationship. Any arrow moving toward the Some relationship does not transfer back the Some relationship. For example:
A --> B <-some-> C
Relationship between A and C is unknown, as per @MrSamlam's very detailed explanation.
Unfortunately @quinnxzhang I haven't taken formal first-order logic so I'm not familiar with your diagramming method but I thank you nonetheless.