Sometimes Not Question

Comments

• canihazJD Alum Member Sage ⭐

  July 2021 edited July 2021 8491 karma

  edit... it looks like you are saying this?

  A ←s→ /B
  B ←s→ /A

  In which case, no they are not.
• hotranchsauce Member

  July 2021 288 karma

  @canihazJD said:
  edit... it looks like you are saying this?

  A ←s→ /B
  B ←s→ /A

  In which case, no they are not.

  Thanks. Let me ask one more question if I can.

  If A is not always B, then A<--s-->/B, correct?

  So then can we or can't we conclude that /A<--s-->B?

  I thought that because "some" goes both ways, that you could put the "/" on either side and have it be equally true. But I obviously have not convinced myself because I'm here talking about it.

  Thanks again for shining any light onto this, I really appreciate it.
• canihazJD Alum Member Sage ⭐

  July 2021 8491 karma

  @businesskarafa said:

  @canihazJD said:
  edit... it looks like you are saying this?

  A ←s→ /B
  B ←s→ /A

  In which case, no they are not.

  Thanks. Let me ask one more question if I can.

  If A is not always B, then A<--s-->/B, correct?

  So then can we or can't we conclude that /A<--s-->B?

  I thought that because "some" goes both ways, that you could put the "/" on either side and have it be equally true. But I obviously have not convinced myself because I'm here talking about it.

  Thanks again for shining any light onto this, I really appreciate it.

  /A ←s→ B might very well be true, but you can't infer it just from A ←s→ /B.

  /A and A are just two sets that don't intersect. They also could just be called △and ☐, △ including everything that is not a ☐.
• hotranchsauce Member

  July 2021 edited July 2021 288 karma

  @canihazJD said:

  @businesskarafa said:

  @canihazJD said:
  edit... it looks like you are saying this?

  A ←s→ /B
  B ←s→ /A

  In which case, no they are not.

  Thanks. Let me ask one more question if I can.

  If A is not always B, then A<--s-->/B, correct?

  So then can we or can't we conclude that /A<--s-->B?

  I thought that because "some" goes both ways, that you could put the "/" on either side and have it be equally true. But I obviously have not convinced myself because I'm here talking about it.

  Thanks again for shining any light onto this, I really appreciate it.

  /A ←s→ B might very well be true, but you can't infer it just from A ←s→ /B.

  /A and A are just two sets that don't intersect. They also could just be called △and ☐, △ including everything that is not a ☐.

  I agree. I was finally able to wrap my head around it. Thanks again for taking time from your day to respond to me.