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Hey guys so I was doing question 4, LR2 preptest 25.
In this question the premise was
a->b->c
and then it concluded c->a
So the correct FMOR answer was
"the argument ignore the facto that some c's may not appreciate a's.
so c -some- a/
Is this a rule that can be applied to all conditional logic? A->B always can also mean B -some- A/?
A bit confused thanks. Hope this all made sense.
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@7sagestudentservices It's against 7Sage's rules to post entire questions!
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no, A-> B doesn't imply "B some not A", but it may. In other words, It might turn out that A->B and, simultaneously, that B->A, which means that "B some not A" doesn't follow. But it also might turn out that B is a circle in which A is just a subset of B, which would mean that There are some B's that are not As. Do you get it?
post the question, it is hard to follow what you are talking about.