Let's say there are 2 As that exist. So we know, all those As are Bs. But what if there are 50 Bs in total? So those 2 As are only a small amount. Then, even if most Bs are Cs, those 2 Bs that are also As could be part of the "most" that are Cs or not. It's unknown.
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3 comments
No, you cannot infer that from the first example.
Let's say there are 2 As that exist. So we know, all those As are Bs. But what if there are 50 Bs in total? So those 2 As are only a small amount. Then, even if most Bs are Cs, those 2 Bs that are also As could be part of the "most" that are Cs or not. It's unknown.
@akikookmt881 Yes that's what I meant. Sorry if I confused you.
I just know that
A → B
B →m→ C
cannot be A → m → C
A → B
B →some→ C
cannot be A → s → C
I want to know if you can get A → s → C from first diagram
@akikookmt881 said:
Can you solve this below?
A - B
Most B - C
A- B
Some B - C
Hey @akikookmt881,
Sorry, I can't really understand what you are writing.
Were you meaning to write as below?
A → B
B -m→ C
A → B
B ←some→ C
And what would you like to "solve" from this?