Remember G3-->Q5, but Q is clearly in 4, so that negates the necessary condition, triggering a negation of the sufficient condition. In other words, G cannot be in 3. That leaves only J and H for slot 3. Hence, answer D
23 questions on LG? I think I made a bubbling error after skipping G3 to do G4 then going back. 24 bubbled lines staring me in the face at the end of the section :-/
-0 on game (i thought i did terrible on G3 but wow I didn't miss one question? i didn't even understand that game) but I screwed up on RC... good luck everyone. this is my last retake... loved 7sage!!
I think you may be talking about Section four and not section two. S4 has the psychic power question:
https://7sage.com/lsat_explanations/lsat-77-section-4-question-20
You can find JY doing LR in PT69 S1+S4, and PT71 S1+S3. And Jon also had an epic timed LR section video, which took him only 19 minutes. https://www.youtube.com/watch?v=F4vY0KpviJw&index=6&list=LLaknkMoRl59wmjfBX67-nFg
... exactly one each of g3 and g4 indicators in a ... rules, (3) remember that g3=g2 and g4=g1 if ... should theoretically always work - g3 negates sufficient and leaves a ... swaps sufficient/necessary (hence g3->g2 and g4-> ... work with a singular g3/g4 indicator and a ...
@dcdcdcdcdc said:
A is wrong because it could be that her daughter is just very wise at birth. Isn't this the same as saying a tree could just start off with a lot of rings?